(1/2x-2/3)^2=1

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Solution for (1/2x-2/3)^2=1 equation: 


x in (-oo:+oo)

((1/2)*x-(2/3))^2 = 1 // - 1

((1/2)*x-(2/3))^2-1 = 0

((1/2)*x-2/3)^2-1 = 0

(1/2*x-2/3)^2-1 = 0

(1/2*x-2/3)^2-1 = 0

1/4*x^2-2/3*x-5/9 = 0

1/4*x^2-2/3*x-5/9 = 0

1/4*x^2-2/3*x-5/9 = 0

DELTA = (-2/3)^2-(-5/9*1/4*4)

DELTA = 1

DELTA > 0

x = (1^(1/2)+2/3)/(1/4*2) or x = (2/3-1^(1/2))/(1/4*2)

x = 10/3 or x = -2/3

(x+2/3)*(x-10/3) = 0

(x+2/3)*(x-10/3) = 0

( x+2/3 )

x+2/3 = 0 // - 2/3

x = -2/3

( x-10/3 )

x-10/3 = 0 // + 10/3

x = 10/3

x in { -2/3, 10/3 }

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